12/3/2023 0 Comments Ap calc optimization problems![]() ![]() We will be continuing optimization problems on Monday.Slide #7 has a question for you to solve.Since we know t=1/29 hr, we put that into d to determine the minimum distance at 10:02am. (Who wants to use chain rule 20 times for deriving an equation? I don't.) We did this so we can find the critical number(s), determine if the critical number(s) is a max or min using the 1st derivative test, then solve for t.Īnswer: t=1/29 hr, which is approx, 2 min, so at 10:02am the cars are closest.Ĥ. (Someone, help me out here.) Then we expand the equation we generated for d, so we can apply the derivative rules as minimum as possible. Because d is a radical function and we're looking for the critical numbers, uh oh, I forgot. Yes, that's my adjective for hypotenuse it's been copyrighted by none other than me, zeph.ģ. Using the chart, we were able to generate a formula for d, the distance or the hypotenuse or the hypotenusal distance. Using the info provided, we organized the info onto a chart, where d=distance, r=velocity (a.k.a. Designated the hypotenuse of the triangle, d.Ģ.The derivative of the distance function is the velocity function. ![]()
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